\(\text{5,95}\) \(\text{g}\) of potassium bromide was dissolved in \(\text{400}\) \(\text{dm$^{3}$}\) of water. Calculate its concentration.
19.3 Amount of substance
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19.2 Composition
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19.4 Stoichiometric calculations
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19.3 Amount of substance (ESAGC)
Molar Volumes of Gases (ESAGD)
- Molar volume of gases
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One mole of gas occupies 22,4 dm3 at standard temperature and pressure.
This applies to any gas that is at standard temperature and pressure. In grade 11 you will learn more about this and the gas laws.
Standard temperature and pressure (S.T.P.) is defined as a temperature of 273,15 K and a pressure of 0,986 atm.
For example, 2 mol of H2 gas will occupy a volume of 44,8 dm3 at standard temperature and pressure (S.T.P.). and 67,2 dm3 of ammonia gas (NH3) contains 3 mol of ammonia.
Molar concentrations of liquids (ESAGE)
A typical solution is made by dissolving some solid substance in a liquid. The amount of substance that is dissolved in a given volume of liquid is known as the concentration of the liquid. Mathematically, concentration (c) is defined as moles of solute (n) per unit volume (V) of solution.
c=nV
For this equation, the units for volume are dm3 (which is equal to litres). Therefore, the unit of concentration is mol·dm−3.
- Concentration
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Concentration is a measure of the amount of solute that is dissolved in a given volume of liquid. It is measured in mol·dm−3.
Worked example 12: Concentration calculations 1
If 3,5 g of sodium hydroxide (NaOH) is dissolved in 2,5 dm3 of water, what is the concentration of the solution in mol·dm−3?
Find the number of moles of sodium hydroxide
n=mM=3,5 g40,01 g·mol−1=0,0875 molCalculate the concentration
c=nV=0,0875 mol2,5 dm3=0,035 mol·dm−3The concentration of the solution is 0,035 mol·dm−3.
Worked example 13: Concentration calculations 2
You have a 1 dm3 container in which to prepare a solution of potassium permanganate (KMnO4). What mass of KMnO4 is needed to make a solution with a concentration of 0,2 mol·dm−3?
Calculate the number of moles
c=nV therefore:
n=c×V=0,2 mol·dm−3×1 dm3=0,2 molFind the mass
m=nM=(0,2 mol)(158 g·mol−1)=31,6 gThe mass of KMnO4 that is needed is 31,6 g.
Worked example 14: Concentration calculations 3
How much sodium chloride (in g) will one need to prepare 500 cm3 of solution with a concentration of 0,01 mol·dm−3?
Convert the given volume to the correct units
V=500 cm3×1 dm31 000 cm3=0,5 dm3Find the number of moles
n=c×V=0,01 mol·dm−3×0,5 dm3=0,005 molFind the mass
m=nM=(0,005 mol)(58,45 g·mol−1)=0,29225 g≈0,29 gThe mass of sodium chloride needed is 0,29 g
Concentration of solutions
\(\text{100}\) \(\text{g}\) of sodium chloride (\(\text{NaCl}\)) is dissolved in \(\text{450}\) \(\text{cm$^{3}$}\) of water.
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How many moles of \(\text{NaCl}\) are present in solution?
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What is the volume of water (in \(\text{dm$^{3}$}\))?
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Calculate the concentration of the solution.
What is the molarity of the solution formed by dissolving \(\text{80}\) \(\text{g}\) of sodium hydroxide (\(\text{NaOH}\)) in \(\text{500}\) \(\text{cm$^{3}$}\) of water?
What mass (g) of hydrogen chloride (\(\text{HCl}\)) is needed to make up \(\text{1 000}\) \(\text{cm$^{3}$}\) of a solution of concentration \(\text{1}\) \(\text{mol·dm$^{-3}$}\)?
How many moles of \(\text{H}_{2}\text{SO}_{4}\) are there in \(\text{250}\) \(\text{cm$^{3}$}\) of a \(\text{0,8}\) \(\text{mol·dm$^{-3}$}\) sulphuric acid solution? What mass of acid is in this solution?
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19.2 Composition
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19.4 Stoichiometric calculations
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