You have learnt previously about the structure of an atom. The electrons
surrounding the atomic nucleus are arranged in a series of levels of increasing
energy. Each element has a unique number of electrons in a unique configuration
therefore each element has its own distinct set of energy levels. This arrangement
of energy levels serves as the atom's unique fingerprint.
In the early 1900s, scientists found that a liquid or solid heated to high
temperatures would give off a broad range of colours of light. However, a gas
heated to similar temperatures would emit light only at certain specific wavelengths
(colours). The reason for this observation was not understood at the time.
Scientists studied this effect using a discharge tube.
A discharge tube (shown in Figure 12.5) is a
gas-filled, glass tube with a metal plate at both ends. If a large enough voltage difference
is applied between the two metal plates, the gas atoms inside the tube will absorb
enough energy to make some of their electrons come off, i.e. the gas atoms are ionised.
These electrons start moving through the gas and create a current, which raises some
electrons in other atoms to higher energy levels. Then as the electrons in the atoms
fall back down, they emit electromagnetic radiation (light). The amount of light
emitted at different wavelengths, called the emission
spectrum, is shown for a discharge tube filled with hydrogen gas in
Figure 12.6 below. Only certain wavelengths (i.e. colours)
of light are seen, as shown by the lines in the picture.
Eventually, scientists realised that these lines come from photons of
a specific energy, emitted by electrons making transitions between specific
energy levels of the atom. Figure 12.7 shows an example
of this happening. When an electron in an atom falls from a higher energy
level to a lower energy level, it emits a photon to carry off the extra energy.
This photon's energy is equal to the energy difference between the two energy
levels
(\(\Delta E\)).
\[\Delta E_{\text{electron}} = E_f - E_i\]
As we previously discussed, the frequency of a photon is related to its
energy through the equation \(E=hf\). Since a specific photon
frequency (or wavelength) gives us a specific colour, we can see how each
coloured line is associated with a specific transition.
Visible light is not the only kind of electromagnetic radiation emitted. More energetic or less energetic
transitions can produce ultraviolet or infrared radiation. However, because each atom has its own distinct set
of energy levels (its fingerprint!), each atom has its own distinct emission spectrum.
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Absorption spectra (ESCQT)
Atoms do not only emit photons; they also absorb photons. If a photon hits an
atom and the energy of the photon is the same as the gap between two electron energy
levels in the atom, then the electron in the lower energy level can absorb the photon
and jump up to the higher energy level. If the photon energy does not correspond
to the difference between two energy levels then the photon will not be absorbed (it
can still be scattered).
Using this effect, if we have a source of photons of various energies we can
obtain the absorption spectra for different materials.
To get an absorption spectrum, just shine white light on a sample of the material that
you are interested in. White light is made up of all the different wavelengths of
visible light put together. In the absorption spectrum there will be gaps.
The gaps correspond to energies (wavelengths) for which there is a corresponding
difference in energy levels for the particular element.
The absorbed photons show up as black lines because the photons of these wavelengths
have been absorbed and do not show up. Because of this, the absorption spectrum is
the exact inverse of the emission spectrum.
Look at the two figures below. In Figure 12.8 you can see
the line emission spectrum of hydrogen. Figure 12.9 shows
the
absorption spectrum. It is the exact opposite of the emission spectrum! Both emission
and absorption techniques can be used to get the same information about
the energy levels of an atom.
The dark lines correspond to the frequencies of light that have been
absorbed by the gas. As the photons of light are absorbed by electrons, the electrons
move into higher energy levels. This is the opposite process of emission.
The dark lines, absorption lines, correspond to the frequencies of the emission
spectrum of the same element. The amount of energy absorbed by the electron to move
into a higher level is the same as the amount of energy released when returning to the
original energy level.
Worked example 4: Absorption
I have an unknown gas in a glass container. I shine a bright white light
through one side of the container and measure the spectrum of transmitted light.
I notice that there is a black line
(absorption line) in the middle of the
visible red band at \(\text{642}\) \(\text{nm}\).
I have a hunch that the gas might be hydrogen. If I am correct, between which
2 energy levels does this transition occur? (Hint: look
at Figure 12.7 and the transitions which are in the visible
part of the spectrum.)
What is given and what needs to be done?
We have an absorption line at \(\text{642}\) \(\text{nm}\). This means that the substance in the glass
container absorbed photons with a wavelength of 642 nm.
We need to calculate which 2 energy levels of hydrogen this transition would correspond to. Therefore we
need to know what energy the absorbed photons had.
The absorbed photons had an energy of \(\text{3,1} \times \text{10}^{-\text{19}}\) \(\text{J}\).
Find the energy of the transitions resulting in radiation at visible wavelengths
Figure 12.7 shows various energy level
transitions. The transitions related to visible wavelengths are marked as
the transitions beginning or ending on Energy Level 2.
Let us find the energy of those transitions and compare with the energy of
the absorbed photons we have just calculated.
Energy of transition (absorption) from Energy Level 2 to Energy Level 3:
Therefore the energy of the photon that an electron must absorb to jump from Energy Level 2 to Energy Level
3 is \(\text{3,1} \times \text{10}^{-\text{19}}\) \(\text{J}\).
(NOTE: The minus sign means that absorption is occurring.)
This is the same energy as the photons which were absorbed by the gas in the container! Therefore, since
the transitions of all elements are unique, we can say that the gas in the container is hydrogen. The
transition is absorption of a photon between Energy Level 2 and Energy Level 3.
The energy of the photon does not correspond to the energy of an energy level, it
corresponds to the difference in energy between two
energy levels.
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Applications of emission and absorption spectra (ESCQV)
The study of spectra from stars and galaxies in astronomy is i
called spectroscopy. Spectroscopy is a
tool widely used in astronomy to learn different things about astronomical objects.
Identifying elements in astronomical objects using their spectra
Measuring the spectrum of light from a star can tell astronomers what the
star is made of. Since each element emits or absorbs light only at particular
wavelengths, astronomers can identify what elements are in the stars from
the lines in their spectra. From studying the spectra of many stars we know
that there are many different types of stars which contain different
elements and in different amounts.
Determining velocities of galaxies using spectroscopy
You have already learnt in Chapter 6
about the Doppler
effect and how the frequency (and wavelength) of sound waves changes
depending on whether the object emitting the sound is moving
towards or
away from you. The same thing happens
to electromagnetic radiation (light). If the object emitting the light is
moving towards us, then the wavelength
of the light appears shorter (called blueshifted).
If the object is moving away from us,
then the wavelength of its light appears stretched out
(called redshifted).
The Doppler effect affects the spectra of objects in
space depending on their motion relative to us on the earth. For
example, the light from a distant galaxy that is moving away from us
at some velocity will appear redshifted. This means that the emission
and absorption lines in the galaxy's spectrum will be shifted to a longer
wavelength (lower frequency). Knowing where each line in the spectrum
would normally be if the galaxy was not moving and comparing it to
the redshifted position, allows astronomers to precisely measure the velocity
of the galaxy relative to the Earth.
Global warming and greenhouse gases
The sun emits radiation (light) over a range of wavelengths that
are mainly in the visible part of the spectrum. Radiation at these
wavelengths passes through the gases of the atmosphere to warm the
land and the oceans below. The warm earth then radiates this heat
at longer infrared wavelengths. Carbon dioxide (one of the main
greenhouse gases) in the atmosphere has energy levels that correspond
to the infrared wavelengths that allow it to absorb the infrared radiation.
It then also emits at infrared wavelengths in all directions. This
effect stops a large amount of the infrared radiation from getting out of the
atmosphere, which causes the atmosphere and the earth to heat up. More
radiation is coming in than is getting back out.
So increasing the amount of greenhouse gases in the atmosphere increases the amount of trapped infrared
radiation and therefore the overall temperature of the earth. The earth is a very sensitive and complicated
system upon which life depends and changing the delicate balances of temperature and atmospheric gas content
may have disastrous consequences if we are not careful.
Emission and absorption spectra
Textbook Exercise 12.2
Explain how atomic emission spectra arise and how they relate to each element on the periodic table.
Atomic emission spectra arise from electrons dropping from higher energy levels to lower energy
levels within the atom, photons (light packets) with specific wavelengths are released. The energy
levels in an atom are specific/unique to each element on the periodic table therefore the wavelength
of light emitted can be used to determine which element the light came from.
How do the lines on the atomic spectrum relate to electron transitions between energy levels?
The lines on the atomic spectrum relate to electron transitions between energy levels, if the
electron drops an energy level a photon is released resulting in an emission line and if the electron
absorbs a photon and rises an energy level an absorption line is observed on the spectrum.
Explain the difference between atomic absorption and emission spectra.
The difference between absorption and emission spectra are that absorption lines are where light has
been absorbed by the atom thus you see a dip in the spectrum whereas emission spectra have spikes in
the spectra due to atoms releasing photons at those wavelengths.
Describe how the absorption and emission spectra of the gases in the atmosphere give rise to the
Greenhouse Effect.
The following needs to be in your answer: in what wavelength range the sunlight reaches the earth,
the absorption of the sunlight and the re-radiation as infrared light, and finally the scattering of
the infrared light by the carbon-dioxide and how this scattering contributes to the Greenhouse Effect.
What colour is the light emitted by hydrogen when an electron makes the transition from energy level
5 down to energy level 2? (Use Figure 12.7 to find the
energy of the released photon.)
\begin{align*}
\lambda & = \frac{hc}{\Delta E} \\
& = \frac{(\text{6,63} \times \text{10}^{-\text{34}}\text{ m$^{2}$kg·s$^{-1}$})(\text{3}
\times \text{10}^{\text{8}}\text{ m·s$^{-1}$})}{\text{4,7} \times \text{10}^{-\text{19}}\text{
J}} \\
& = \text{423}\text{ nm}
\end{align*}
The colour of light emitted at \(\text{423}\) \(\text{nm}\) is violet.
I have a glass tube filled with hydrogen gas. I shine white light onto the tube. The spectrum I then
measure has an absorption line at a wavelength of 474 nm. Between which two energy levels did the
transition occur? (Use Figure 12.7 in solving the
problem.)
\begin{align*}
\Delta E & = \frac{hc}{\lambda} \\
& = \frac{(\text{6,63} \times \text{10}^{-\text{34}}\text{ m$^{2}$kg·s$^{-1}$})(\text{3}
\times \text{10}^{\text{8}}\text{ m·s$^{-1}$})}{\text{474} \times \text{10}^{-\text{9}}\text{
nm}}\\
& = \text{4,20} \times \text{10}^{-\text{19}}\text{ J}
\end{align*}
This energy interval corresponds to a transition from energy level 4 to energy level 2.